Base | Representation |
---|---|
bin | 1101101100111011100100… |
… | …01011001011000110001110 |
3 | 10221200111122221101101202001 |
4 | 12312131302023023012032 |
5 | 12422132003421104402 |
6 | 144030012533222514 |
7 | 6226621010433316 |
oct | 666356213130616 |
9 | 127614587341661 |
10 | 30131111113102 |
11 | 966759478597a |
12 | 3467740191a3a |
13 | 13a7475585b4c |
14 | 7624d4248446 |
15 | 373ba546b187 |
hex | 1b67722cb18e |
30131111113102 has 4 divisors (see below), whose sum is σ = 45196666669656. Its totient is φ = 15065555556550.
The previous prime is 30131111113091. The next prime is 30131111113109. The reversal of 30131111113102 is 20131111113103.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 30131111113102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30131111113109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7532777778274 + ... + 7532777778277.
It is an arithmetic number, because the mean of its divisors is an integer number (11299166667414).
Almost surely, 230131111113102 is an apocalyptic number.
30131111113102 is a deficient number, since it is larger than the sum of its proper divisors (15065555556554).
30131111113102 is a wasteful number, since it uses less digits than its factorization.
30131111113102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15065555556553.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 30131111113102 its reverse (20131111113103), we get a palindrome (50262222226205).
Subtracting from 30131111113102 its reverse (20131111113103), we obtain a palindrome (9999999999999).
The spelling of 30131111113102 in words is "thirty trillion, one hundred thirty-one billion, one hundred eleven million, one hundred thirteen thousand, one hundred two".
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