Base | Representation |
---|---|
bin | 1000110010100111100… |
… | …10011010001100010011 |
3 | 1001212122121211021211002 |
4 | 10121103302122030103 |
5 | 14422101134343011 |
6 | 350432245212215 |
7 | 30552110553641 |
oct | 4312362321423 |
9 | 1055577737732 |
10 | 302053434131 |
11 | 10711131a7a9 |
12 | 4a65910106b |
13 | 226393944a7 |
14 | 10895b4a191 |
15 | 7cccac8c3b |
hex | 4653c9a313 |
302053434131 has 2 divisors, whose sum is σ = 302053434132. Its totient is φ = 302053434130.
The previous prime is 302053434127. The next prime is 302053434143. The reversal of 302053434131 is 131434350203.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 302053434131 - 22 = 302053434127 is a prime.
It is a super-2 number, since 2×3020534341312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 302053434094 and 302053434103.
It is not a weakly prime, because it can be changed into another prime (302053434181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 151026717065 + 151026717066.
It is an arithmetic number, because the mean of its divisors is an integer number (151026717066).
Almost surely, 2302053434131 is an apocalyptic number.
302053434131 is a deficient number, since it is larger than the sum of its proper divisors (1).
302053434131 is an equidigital number, since it uses as much as digits as its factorization.
302053434131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 302053434131 its reverse (131434350203), we get a palindrome (433487784334).
The spelling of 302053434131 in words is "three hundred two billion, fifty-three million, four hundred thirty-four thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •