Base | Representation |
---|---|
bin | 1101101111010100111010… |
… | …11111000010111000100011 |
3 | 10221222101011201200221210011 |
4 | 12313222131133002320203 |
5 | 12430004112140340001 |
6 | 144131510320345351 |
7 | 6235564155444124 |
oct | 667523537027043 |
9 | 127871151627704 |
10 | 30213442121251 |
11 | 96994a3461974 |
12 | 347b698775257 |
13 | 13b21665cb90c |
14 | 7664a480404b |
15 | 375dc33d3d51 |
hex | 1b7a9d7c2e23 |
30213442121251 has 2 divisors, whose sum is σ = 30213442121252. Its totient is φ = 30213442121250.
The previous prime is 30213442121221. The next prime is 30213442121279. The reversal of 30213442121251 is 15212124431203.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 30213442121251 - 243 = 21417349099043 is a prime.
It is not a weakly prime, because it can be changed into another prime (30213442121221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15106721060625 + 15106721060626.
It is an arithmetic number, because the mean of its divisors is an integer number (15106721060626).
Almost surely, 230213442121251 is an apocalyptic number.
30213442121251 is a deficient number, since it is larger than the sum of its proper divisors (1).
30213442121251 is an equidigital number, since it uses as much as digits as its factorization.
30213442121251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 30213442121251 its reverse (15212124431203), we get a palindrome (45425566552454).
The spelling of 30213442121251 in words is "thirty trillion, two hundred thirteen billion, four hundred forty-two million, one hundred twenty-one thousand, two hundred fifty-one".
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