Base | Representation |
---|---|
bin | 1101101111101001010101… |
… | …01001010011101001011011 |
3 | 10222000102110102111210212111 |
4 | 12313310222221103221123 |
5 | 12430144032441132103 |
6 | 144140521533053151 |
7 | 6236432546634403 |
oct | 667645251235133 |
9 | 128012412453774 |
10 | 30224400333403 |
11 | 96a3107048951 |
12 | 34818366271b7 |
13 | 13b31c1984a13 |
14 | 766c23d17803 |
15 | 37631546b86d |
hex | 1b7d2aa53a5b |
30224400333403 has 2 divisors, whose sum is σ = 30224400333404. Its totient is φ = 30224400333402.
The previous prime is 30224400333293. The next prime is 30224400333443. The reversal of 30224400333403 is 30433300442203.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 30224400333403 - 217 = 30224400202331 is a prime.
It is a super-2 number, since 2×302244003334032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (30224400333443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15112200166701 + 15112200166702.
It is an arithmetic number, because the mean of its divisors is an integer number (15112200166702).
Almost surely, 230224400333403 is an apocalyptic number.
30224400333403 is a deficient number, since it is larger than the sum of its proper divisors (1).
30224400333403 is an equidigital number, since it uses as much as digits as its factorization.
30224400333403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 31.
Adding to 30224400333403 its reverse (30433300442203), we get a palindrome (60657700775606).
The spelling of 30224400333403 in words is "thirty trillion, two hundred twenty-four billion, four hundred million, three hundred thirty-three thousand, four hundred three".
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