30251114130045 has 8 divisors (see below), whose sum is σ = 48401782608096. Its totient is φ = 16133927536016.

The previous prime is 30251114130019. The next prime is 30251114130047. The reversal of 30251114130045 is 54003141115203.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 30251114130045 - 2⁷ = 30251114129917 is a prime.

It is a super-2 number, since 2×30251114130045² (a number of 28 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 30251114129994 and 30251114130021.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (30251114130047) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1008370470987 + ... + 1008370471016.

It is an arithmetic number, because the mean of its divisors is an integer number (6050222826012).

Almost surely, 2^{30251114130045} is an apocalyptic number.

It is an amenable number.

30251114130045 is a deficient number, since it is larger than the sum of its proper divisors (18150668478051).

30251114130045 is a wasteful number, since it uses less digits than its factorization.

30251114130045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2016740942011.

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 30251114130045 its reverse (54003141115203), we get a palindrome (84254255245248).

The spelling of 30251114130045 in words is "thirty trillion, two hundred fifty-one billion, one hundred fourteen million, one hundred thirty thousand, forty-five".