Base | Representation |
---|---|
bin | 101100000101101000010… |
… | …011111010011001100011 |
3 | 101201122012010210220120001 |
4 | 230011220103322121203 |
5 | 344114312202302313 |
6 | 10235454220200431 |
7 | 431613561020032 |
oct | 54055023723143 |
9 | 11648163726501 |
10 | 3029701994083 |
11 | a68986878526 |
12 | 40b215099117 |
13 | 18c913244a2b |
14 | a68d192a719 |
15 | 53c22104add |
hex | 2c1684fa663 |
3029701994083 has 2 divisors, whose sum is σ = 3029701994084. Its totient is φ = 3029701994082.
The previous prime is 3029701994057. The next prime is 3029701994113. The reversal of 3029701994083 is 3804991079203.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3029701994083 is a prime.
It is not a weakly prime, because it can be changed into another prime (3029701994003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1514850997041 + 1514850997042.
It is an arithmetic number, because the mean of its divisors is an integer number (1514850997042).
Almost surely, 23029701994083 is an apocalyptic number.
3029701994083 is a deficient number, since it is larger than the sum of its proper divisors (1).
3029701994083 is an equidigital number, since it uses as much as digits as its factorization.
3029701994083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2939328, while the sum is 55.
The spelling of 3029701994083 in words is "three trillion, twenty-nine billion, seven hundred one million, nine hundred ninety-four thousand, eighty-three".
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