Base | Representation |
---|---|
bin | 101100000110110101101… |
… | …100100110011000011011 |
3 | 101201202112121211020222202 |
4 | 230012311230212120123 |
5 | 344124442034430243 |
6 | 10240231115440415 |
7 | 431661004361345 |
oct | 54066554463033 |
9 | 11652477736882 |
10 | 3031000311323 |
11 | a69492726486 |
12 | 40b517a5610b |
13 | 18ca8c210a9a |
14 | a69b6130295 |
15 | 53c9b0b14b8 |
hex | 2c1b5b2661b |
3031000311323 has 2 divisors, whose sum is σ = 3031000311324. Its totient is φ = 3031000311322.
The previous prime is 3031000311271. The next prime is 3031000311329. The reversal of 3031000311323 is 3231130001303.
3031000311323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3031000311323 - 212 = 3031000307227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3031000311295 and 3031000311304.
It is not a weakly prime, because it can be changed into another prime (3031000311329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1515500155661 + 1515500155662.
It is an arithmetic number, because the mean of its divisors is an integer number (1515500155662).
Almost surely, 23031000311323 is an apocalyptic number.
3031000311323 is a deficient number, since it is larger than the sum of its proper divisors (1).
3031000311323 is an equidigital number, since it uses as much as digits as its factorization.
3031000311323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 20.
Adding to 3031000311323 its reverse (3231130001303), we get a palindrome (6262130312626).
The spelling of 3031000311323 in words is "three trillion, thirty-one billion, three hundred eleven thousand, three hundred twenty-three".
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