Base | Representation |
---|---|
bin | 101100000110110101110… |
… | …011000001011101110001 |
3 | 101201202112201222210201122 |
4 | 230012311303001131301 |
5 | 344124443002320441 |
6 | 10240231215512025 |
7 | 431661024603362 |
oct | 54066563013561 |
9 | 11652481883648 |
10 | 3031001995121 |
11 | a69493676551 |
12 | 40b518528615 |
13 | 18ca8c680309 |
14 | a69b644bb69 |
15 | 53c9b2e534b |
hex | 2c1b5cc1771 |
3031001995121 has 2 divisors, whose sum is σ = 3031001995122. Its totient is φ = 3031001995120.
The previous prime is 3031001995057. The next prime is 3031001995139. The reversal of 3031001995121 is 1215991001303.
3031001995121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2995305183025 + 35696812096 = 1730695^2 + 188936^2 .
It is a cyclic number.
It is not a de Polignac number, because 3031001995121 - 26 = 3031001995057 is a prime.
It is not a weakly prime, because it can be changed into another prime (3031001895121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1515500997560 + 1515500997561.
It is an arithmetic number, because the mean of its divisors is an integer number (1515500997561).
Almost surely, 23031001995121 is an apocalyptic number.
It is an amenable number.
3031001995121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3031001995121 is an equidigital number, since it uses as much as digits as its factorization.
3031001995121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7290, while the sum is 35.
Adding to 3031001995121 its reverse (1215991001303), we get a palindrome (4246992996424).
The spelling of 3031001995121 in words is "three trillion, thirty-one billion, one million, nine hundred ninety-five thousand, one hundred twenty-one".
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