Base | Representation |
---|---|
bin | 101100001001000001010… |
… | …101101011001110110001 |
3 | 101201222120220012212111101 |
4 | 230021001111223032301 |
5 | 344144241314041423 |
6 | 10241255410044401 |
7 | 432103033014346 |
oct | 54110125531661 |
9 | 11658526185441 |
10 | 3033343112113 |
11 | a6a485120386 |
12 | 40ba70579701 |
13 | 1900736c0542 |
14 | a6b593407cd |
15 | 53d86ad97ad |
hex | 2c24156b3b1 |
3033343112113 has 2 divisors, whose sum is σ = 3033343112114. Its totient is φ = 3033343112112.
The previous prime is 3033343112099. The next prime is 3033343112123. The reversal of 3033343112113 is 3112113433303.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3032449580449 + 893531664 = 1741393^2 + 29892^2 .
It is a cyclic number.
It is not a de Polignac number, because 3033343112113 - 241 = 834319856561 is a prime.
It is not a weakly prime, because it can be changed into another prime (3033343112123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1516671556056 + 1516671556057.
It is an arithmetic number, because the mean of its divisors is an integer number (1516671556057).
Almost surely, 23033343112113 is an apocalyptic number.
It is an amenable number.
3033343112113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3033343112113 is an equidigital number, since it uses as much as digits as its factorization.
3033343112113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 3033343112113 its reverse (3112113433303), we get a palindrome (6145456545416).
The spelling of 3033343112113 in words is "three trillion, thirty-three billion, three hundred forty-three million, one hundred twelve thousand, one hundred thirteen".
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