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3033343112113 is a prime number
BaseRepresentation
bin101100001001000001010…
…101101011001110110001
3101201222120220012212111101
4230021001111223032301
5344144241314041423
610241255410044401
7432103033014346
oct54110125531661
911658526185441
103033343112113
11a6a485120386
1240ba70579701
131900736c0542
14a6b593407cd
1553d86ad97ad
hex2c24156b3b1

3033343112113 has 2 divisors, whose sum is σ = 3033343112114. Its totient is φ = 3033343112112.

The previous prime is 3033343112099. The next prime is 3033343112123. The reversal of 3033343112113 is 3112113433303.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3032449580449 + 893531664 = 1741393^2 + 29892^2 .

It is a cyclic number.

It is not a de Polignac number, because 3033343112113 - 241 = 834319856561 is a prime.

It is not a weakly prime, because it can be changed into another prime (3033343112123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1516671556056 + 1516671556057.

It is an arithmetic number, because the mean of its divisors is an integer number (1516671556057).

Almost surely, 23033343112113 is an apocalyptic number.

It is an amenable number.

3033343112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3033343112113 is an equidigital number, since it uses as much as digits as its factorization.

3033343112113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 28.

Adding to 3033343112113 its reverse (3112113433303), we get a palindrome (6145456545416).

The spelling of 3033343112113 in words is "three trillion, thirty-three billion, three hundred forty-three million, one hundred twelve thousand, one hundred thirteen".