Base | Representation |
---|---|
bin | 1101110011000100011001… |
… | …11101111110001000001011 |
3 | 10222102200001010102212120222 |
4 | 12321202030331332020023 |
5 | 12434110421043100233 |
6 | 144310532342540255 |
7 | 6251065251616106 |
oct | 671421475761013 |
9 | 128380033385528 |
10 | 30342014034443 |
11 | 9738a809a9271 |
12 | 34a059b13768b |
13 | 13c131666c767 |
14 | 76c7c036973d |
15 | 3793eaba5898 |
hex | 1b988cf7e20b |
30342014034443 has 2 divisors, whose sum is σ = 30342014034444. Its totient is φ = 30342014034442.
The previous prime is 30342014034433. The next prime is 30342014034503. The reversal of 30342014034443 is 34443041024303.
It is a weak prime.
It is an emirp because it is prime and its reverse (34443041024303) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 30342014034443 - 26 = 30342014034379 is a prime.
It is not a weakly prime, because it can be changed into another prime (30342014034403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15171007017221 + 15171007017222.
It is an arithmetic number, because the mean of its divisors is an integer number (15171007017222).
Almost surely, 230342014034443 is an apocalyptic number.
30342014034443 is a deficient number, since it is larger than the sum of its proper divisors (1).
30342014034443 is an equidigital number, since it uses as much as digits as its factorization.
30342014034443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 30342014034443 its reverse (34443041024303), we get a palindrome (64785055058746).
The spelling of 30342014034443 in words is "thirty trillion, three hundred forty-two billion, fourteen million, thirty-four thousand, four hundred forty-three".
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