Base | Representation |
---|---|
bin | 100010011111110101011100… |
… | …0011001010110000100011011 |
3 | 1110210101211012212100022010201 |
4 | 1010333222320121112010123 |
5 | 304233100301434123024 |
6 | 2553211324132123031 |
7 | 120625666563233326 |
oct | 10477527031260433 |
9 | 1423354185308121 |
10 | 303442533114139 |
11 | 8876028a2377a1 |
12 | 2a049242466477 |
13 | 1004167b37a2c3 |
14 | 54d09a868d7bd |
15 | 2513383a50744 |
hex | 113fab865611b |
303442533114139 has 2 divisors, whose sum is σ = 303442533114140. Its totient is φ = 303442533114138.
The previous prime is 303442533114059. The next prime is 303442533114143. The reversal of 303442533114139 is 931411335244303.
It is a strong prime.
It is an emirp because it is prime and its reverse (931411335244303) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 303442533114139 - 235 = 303408173375771 is a prime.
It is a super-2 number, since 2×3034425331141392 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (303442533114439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 151721266557069 + 151721266557070.
It is an arithmetic number, because the mean of its divisors is an integer number (151721266557070).
Almost surely, 2303442533114139 is an apocalyptic number.
303442533114139 is a deficient number, since it is larger than the sum of its proper divisors (1).
303442533114139 is an equidigital number, since it uses as much as digits as its factorization.
303442533114139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1399680, while the sum is 46.
The spelling of 303442533114139 in words is "three hundred three trillion, four hundred forty-two billion, five hundred thirty-three million, one hundred fourteen thousand, one hundred thirty-nine".
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