Base | Representation |
---|---|
bin | 1101110100110110010010… |
… | …00011000011101101001001 |
3 | 10222122111211220110002212221 |
4 | 12322123021003003231021 |
5 | 12441111123243334423 |
6 | 144355003123534041 |
7 | 6255361303100446 |
oct | 672331103035511 |
9 | 128574756402787 |
10 | 30403151543113 |
11 | 97619a448a438 |
12 | 34b0401b2a321 |
13 | 13c700a9811ab |
14 | 77173dd229cd |
15 | 37acc81ece5d |
hex | 1ba6c90c3b49 |
30403151543113 has 8 divisors (see below), whose sum is σ = 30409704287456. Its totient is φ = 30396599200800.
The previous prime is 30403151543111. The next prime is 30403151543117. The reversal of 30403151543113 is 31134515130403.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 30403151543113 - 21 = 30403151543111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (30403151543111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 188009773 + ... + 188171413.
It is an arithmetic number, because the mean of its divisors is an integer number (3801213035932).
Almost surely, 230403151543113 is an apocalyptic number.
It is an amenable number.
30403151543113 is a deficient number, since it is larger than the sum of its proper divisors (6552744343).
30403151543113 is a wasteful number, since it uses less digits than its factorization.
30403151543113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 201015.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 30403151543113 its reverse (31134515130403), we get a palindrome (61537666673516).
The spelling of 30403151543113 in words is "thirty trillion, four hundred three billion, one hundred fifty-one million, five hundred forty-three thousand, one hundred thirteen".
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