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30403151543117 is a prime number
BaseRepresentation
bin1101110100110110010010…
…00011000011101101001101
310222122111211220110002220002
412322123021003003231031
512441111123243334432
6144355003123534045
76255361303100453
oct672331103035515
9128574756402802
1030403151543117
1197619a448a441
1234b0401b2a325
1313c700a9811b2
1477173dd229d3
1537acc81ece62
hex1ba6c90c3b4d

30403151543117 has 2 divisors, whose sum is σ = 30403151543118. Its totient is φ = 30403151543116.

The previous prime is 30403151543111. The next prime is 30403151543143. The reversal of 30403151543117 is 71134515130403.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22782493156201 + 7620658386916 = 4773101^2 + 2760554^2 .

It is a cyclic number.

It is not a de Polignac number, because 30403151543117 - 228 = 30402883107661 is a prime.

It is a super-3 number, since 3×304031515431173 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (30403151543111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15201575771558 + 15201575771559.

It is an arithmetic number, because the mean of its divisors is an integer number (15201575771559).

Almost surely, 230403151543117 is an apocalyptic number.

It is an amenable number.

30403151543117 is a deficient number, since it is larger than the sum of its proper divisors (1).

30403151543117 is an equidigital number, since it uses as much as digits as its factorization.

30403151543117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75600, while the sum is 38.

The spelling of 30403151543117 in words is "thirty trillion, four hundred three billion, one hundred fifty-one million, five hundred forty-three thousand, one hundred seventeen".