Base | Representation |
---|---|
bin | 1101110100110110100101… |
… | …01100101100100100100001 |
3 | 10222122112021012002222222012 |
4 | 12322123102230230210201 |
5 | 12441111441221001340 |
6 | 144355031150122305 |
7 | 6255365310234110 |
oct | 672332254544441 |
9 | 128575235088865 |
10 | 30403313453345 |
11 | 9761a77916a48 |
12 | 34b04481b0395 |
13 | 13c7035390271 |
14 | 77175762bc77 |
15 | 37acd7531565 |
hex | 1ba6d2b2c921 |
30403313453345 has 32 divisors (see below), whose sum is σ = 42381447056640. Its totient is φ = 20505280400640.
The previous prime is 30403313453323. The next prime is 30403313453423. The reversal of 30403313453345 is 54335431330403.
It is not a de Polignac number, because 30403313453345 - 210 = 30403313452321 is a prime.
It is a super-2 number, since 2×304033134533452 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 48170174 + ... + 48797256.
It is an arithmetic number, because the mean of its divisors is an integer number (1324420220520).
Almost surely, 230403313453345 is an apocalyptic number.
30403313453345 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
30403313453345 is a deficient number, since it is larger than the sum of its proper divisors (11978133603295).
30403313453345 is a wasteful number, since it uses less digits than its factorization.
30403313453345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 649865.
The product of its (nonzero) digits is 1166400, while the sum is 41.
Adding to 30403313453345 its reverse (54335431330403), we get a palindrome (84738744783748).
The spelling of 30403313453345 in words is "thirty trillion, four hundred three billion, three hundred thirteen million, four hundred fifty-three thousand, three hundred forty-five".
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