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3040332025 = 52199077057
BaseRepresentation
bin1011010100110111…
…1100100011111001
321211212220212110211
42311031330203321
522211311111100
61221404511121
7135225252523
oct26515744371
97755825424
103040332025
1113202084a5
1270a24b4a1
13395b66243
1420bb04a13
1512bdae1ba
hexb537c8f9

3040332025 has 24 divisors (see below), whose sum is σ = 3973371680. Its totient is φ = 2301384960.

The previous prime is 3040332023. The next prime is 3040332041. The reversal of 3040332025 is 5202330403.

It is not a de Polignac number, because 3040332025 - 21 = 3040332023 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3040331987 and 3040332005.

It is not an unprimeable number, because it can be changed into a prime (3040332023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 427297 + ... + 434353.

Almost surely, 23040332025 is an apocalyptic number.

It is an amenable number.

3040332025 is a deficient number, since it is larger than the sum of its proper divisors (933039655).

3040332025 is a wasteful number, since it uses less digits than its factorization.

3040332025 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7993 (or 7988 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 22.

The square root of 3040332025 is about 55139.2058793015. The cubic root of 3040332025 is about 1448.6840260013.

Adding to 3040332025 its reverse (5202330403), we get a palindrome (8242662428).

The spelling of 3040332025 in words is "three billion, forty million, three hundred thirty-two thousand, twenty-five".

Divisors: 1 5 19 25 95 475 907 4535 7057 17233 22675 35285 86165 134083 176425 430825 670415 3352075 6400699 32003495 121613281 160017475 608066405 3040332025