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30404040433 = 132338772341
BaseRepresentation
bin11100010100001110…
…001101011011110001
32220110220120021122121
4130110032031123301
5444231413243213
621544544034241
72124304036204
oct342416153361
986426507577
1030404040433
1111992319648
125a86302981
132b36cbc790
141685d8193b
15bce33988d
hex71438d6f1

30404040433 has 4 divisors (see below), whose sum is σ = 32742812788. Its totient is φ = 28065268080.

The previous prime is 30404040427. The next prime is 30404040437. The reversal of 30404040433 is 33404040403.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3136784049 + 27267256384 = 56007^2 + 165128^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-30404040433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 30404040398 and 30404040407.

It is not an unprimeable number, because it can be changed into a prime (30404040437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1169386158 + ... + 1169386183.

It is an arithmetic number, because the mean of its divisors is an integer number (8185703197).

Almost surely, 230404040433 is an apocalyptic number.

It is an amenable number.

30404040433 is a deficient number, since it is larger than the sum of its proper divisors (2338772355).

30404040433 is a wasteful number, since it uses less digits than its factorization.

30404040433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2338772354.

The product of its (nonzero) digits is 6912, while the sum is 25.

Adding to 30404040433 its reverse (33404040403), we get a palindrome (63808080836).

The spelling of 30404040433 in words is "thirty billion, four hundred four million, forty thousand, four hundred thirty-three".

Divisors: 1 13 2338772341 30404040433