Base | Representation |
---|---|
bin | 101100001111100111111… |
… | …100001110111111011101 |
3 | 101202122220000110220210010 |
4 | 230033213330032333131 |
5 | 344303301400031323 |
6 | 10244431123233433 |
7 | 432443524554615 |
oct | 54174774167735 |
9 | 11678800426703 |
10 | 3040433205213 |
11 | a7249330a258 |
12 | 41130ab18879 |
13 | 19093357b8c1 |
14 | a722cc2da45 |
15 | 5414e29cc93 |
hex | 2c3e7f0efdd |
3040433205213 has 8 divisors (see below), whose sum is σ = 4055547571488. Its totient is φ = 2026137154544.
The previous prime is 3040433205211. The next prime is 3040433205217. The reversal of 3040433205213 is 3125023340403.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3040433205213 - 21 = 3040433205211 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3040433205211) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 204570231 + ... + 204585092.
It is an arithmetic number, because the mean of its divisors is an integer number (506943446436).
Almost surely, 23040433205213 is an apocalyptic number.
It is an amenable number.
3040433205213 is a deficient number, since it is larger than the sum of its proper divisors (1015114366275).
3040433205213 is a wasteful number, since it uses less digits than its factorization.
3040433205213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 409157803.
The product of its (nonzero) digits is 25920, while the sum is 30.
Adding to 3040433205213 its reverse (3125023340403), we get a palindrome (6165456545616).
The spelling of 3040433205213 in words is "three trillion, forty billion, four hundred thirty-three million, two hundred five thousand, two hundred thirteen".
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