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304044114341257 is a prime number
BaseRepresentation
bin100010100100001101100100…
…1011011100110110110001001
31110212112100000002120000110021
41011020123021123212312021
5304322424321232410012
62554351534325420441
7121020314406263053
oct10510331133466611
91425470002500407
10304044114341257
118897242614a664
122a12595286a721
1310086310799854
145511b5693c8d3
152523d42610007
hex11486c96e6d89

304044114341257 has 2 divisors, whose sum is σ = 304044114341258. Its totient is φ = 304044114341256.

The previous prime is 304044114341167. The next prime is 304044114341299. The reversal of 304044114341257 is 752143411440403.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 260316894966921 + 43727219374336 = 16134339^2 + 6612656^2 .

It is an emirp because it is prime and its reverse (752143411440403) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 304044114341257 - 235 = 304009754602889 is a prime.

It is not a weakly prime, because it can be changed into another prime (304044114341057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 152022057170628 + 152022057170629.

It is an arithmetic number, because the mean of its divisors is an integer number (152022057170629).

Almost surely, 2304044114341257 is an apocalyptic number.

It is an amenable number.

304044114341257 is a deficient number, since it is larger than the sum of its proper divisors (1).

304044114341257 is an equidigital number, since it uses as much as digits as its factorization.

304044114341257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 645120, while the sum is 43.

The spelling of 304044114341257 in words is "three hundred four trillion, forty-four billion, one hundred fourteen million, three hundred forty-one thousand, two hundred fifty-seven".