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3041030214113 is a prime number
BaseRepresentation
bin101100010000001011100…
…001101001000111100001
3101202201102121212010000212
4230100023201221013201
5344311012213322423
610245010251223505
7432464364215423
oct54201341510741
911681377763025
103041030214113
11a7276a304941
12411456a47b95
131909ca16abc8
14a7288238813
15541868c9578
hex2c40b8691e1

3041030214113 has 2 divisors, whose sum is σ = 3041030214114. Its totient is φ = 3041030214112.

The previous prime is 3041030214107. The next prime is 3041030214127. The reversal of 3041030214113 is 3114120301403.

3041030214113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3009642068224 + 31388145889 = 1734832^2 + 177167^2 .

It is a cyclic number.

It is not a de Polignac number, because 3041030214113 - 216 = 3041030148577 is a prime.

It is not a weakly prime, because it can be changed into another prime (3041030214163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1520515107056 + 1520515107057.

It is an arithmetic number, because the mean of its divisors is an integer number (1520515107057).

Almost surely, 23041030214113 is an apocalyptic number.

It is an amenable number.

3041030214113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3041030214113 is an equidigital number, since it uses as much as digits as its factorization.

3041030214113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 3041030214113 its reverse (3114120301403), we get a palindrome (6155150515516).

The spelling of 3041030214113 in words is "three trillion, forty-one billion, thirty million, two hundred fourteen thousand, one hundred thirteen".