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304110113 is a prime number
BaseRepresentation
bin10010001000000…
…101101000100001
3210012020101122112
4102020011220201
51110323010423
650102045105
710351615256
oct2210055041
9705211575
10304110113
1114673147a
1285a19795
134b009818
142c56342d
151ba71a78
hex12205a21

304110113 has 2 divisors, whose sum is σ = 304110114. Its totient is φ = 304110112.

The previous prime is 304110101. The next prime is 304110133. The reversal of 304110113 is 311011403.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 199600384 + 104509729 = 14128^2 + 10223^2 .

It is an emirp because it is prime and its reverse (311011403) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 304110113 - 24 = 304110097 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (304110133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 152055056 + 152055057.

It is an arithmetic number, because the mean of its divisors is an integer number (152055057).

Almost surely, 2304110113 is an apocalyptic number.

It is an amenable number.

304110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

304110113 is an equidigital number, since it uses as much as digits as its factorization.

304110113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 304110113 is about 17438.7531951112. The cubic root of 304110113 is about 672.4762551559.

Adding to 304110113 its reverse (311011403), we get a palindrome (615121516).

The spelling of 304110113 in words is "three hundred four million, one hundred ten thousand, one hundred thirteen".