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30413025413035 = 541479309720713
BaseRepresentation
bin1101110101001000101011…
…00100111000011110101011
310222200110100000212200001221
412322210111210320132223
512441241334001204120
6144403315003122511
76256161056440306
oct672442544703653
9128613300780057
1030413025413035
119766100a86011
1234b22b8813437
1313c7c224a9485
14771dd9411b3d
1537b1a4e940aa
hex1ba9159387ab

30413025413035 has 16 divisors (see below), whose sum is σ = 37463817565440. Its totient is φ = 23687440053760.

The previous prime is 30413025412963. The next prime is 30413025413041. The reversal of 30413025413035 is 53031452031403.

It is not a de Polignac number, because 30413025413035 - 215 = 30413025380267 is a prime.

It is a super-2 number, since 2×304130254130352 (a number of 28 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 154762162 + ... + 154958551.

It is an arithmetic number, because the mean of its divisors is an integer number (2341488597840).

Almost surely, 230413025413035 is an apocalyptic number.

30413025413035 is a deficient number, since it is larger than the sum of its proper divisors (7050792152405).

30413025413035 is a wasteful number, since it uses less digits than its factorization.

30413025413035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 309721238.

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 30413025413035 its reverse (53031452031403), we get a palindrome (83444477444438).

The spelling of 30413025413035 in words is "thirty trillion, four hundred thirteen billion, twenty-five million, four hundred thirteen thousand, thirty-five".

Divisors: 1 5 41 205 479 2395 19639 98195 309720713 1548603565 12698549233 63492746165 148356221527 741781107635 6082605082607 30413025413035