Base | Representation |
---|---|
bin | 11000000111011010110001… |
… | …10111000011100110101011 |
3 | 20221202202110001222021120221 |
4 | 30003231120313003212223 |
5 | 23422331403210001103 |
6 | 304442151315030511 |
7 | 14112252550504606 |
oct | 1403553067034653 |
9 | 227682401867527 |
10 | 53031452031403 |
11 | 1599657016554a |
12 | 5b45a25b9b437 |
13 | 2378ac93b3641 |
14 | d14a4372333d |
15 | 61e70a6ee1bd |
hex | 303b58dc39ab |
53031452031403 has 32 divisors (see below), whose sum is σ = 55319626801152. Its totient is φ = 50782331289600.
The previous prime is 53031452031373. The next prime is 53031452031431. The reversal of 53031452031403 is 30413025413035.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53031452031403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53031452031443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2962145550 + ... + 2962163452.
It is an arithmetic number, because the mean of its divisors is an integer number (1728738337536).
Almost surely, 253031452031403 is an apocalyptic number.
53031452031403 is a deficient number, since it is larger than the sum of its proper divisors (2288174769749).
53031452031403 is a wasteful number, since it uses less digits than its factorization.
53031452031403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20635.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 53031452031403 its reverse (30413025413035), we get a palindrome (83444477444438).
The spelling of 53031452031403 in words is "fifty-three trillion, thirty-one billion, four hundred fifty-two million, thirty-one thousand, four hundred three".
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