Base | Representation |
---|---|
bin | 101100010000011101101… |
… | …001110000100000001011 |
3 | 101202202012211002212112012 |
4 | 230100131221300200023 |
5 | 344312123042101103 |
6 | 10245100353410135 |
7 | 432505046163644 |
oct | 54203551604013 |
9 | 11682184085465 |
10 | 3041334331403 |
11 | a72905a40745 |
12 | 41152086994b |
13 | 190a4817aa74 |
14 | a72b67a06cb |
15 | 541a344d2d8 |
hex | 2c41da7080b |
3041334331403 has 24 divisors (see below), whose sum is σ = 3093059179104. Its totient is φ = 2990386022400.
The previous prime is 3041334331369. The next prime is 3041334331421.
3041334331403 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 3041334331403 - 216 = 3041334265867 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 3041334331403.
It is not an unprimeable number, because it can be changed into a prime (3041334331003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1620315701 + ... + 1620317577.
It is an arithmetic number, because the mean of its divisors is an integer number (128877465796).
Almost surely, 23041334331403 is an apocalyptic number.
3041334331403 is a deficient number, since it is larger than the sum of its proper divisors (51724847701).
3041334331403 is a wasteful number, since it uses less digits than its factorization.
3041334331403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3095 (or 2994 counting only the distinct ones).
The product of its (nonzero) digits is 46656, while the sum is 32.
The spelling of 3041334331403 in words is "three trillion, forty-one billion, three hundred thirty-four million, three hundred thirty-one thousand, four hundred three".
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