Base | Representation |
---|---|
bin | 11100010100110101… |
… | …100011011011001001 |
3 | 2220111121222021101001 |
4 | 130110311203123021 |
5 | 444242033312441 |
6 | 21545553055001 |
7 | 2124460513234 |
oct | 342465433311 |
9 | 86447867331 |
10 | 30414354121 |
11 | 11998123458 |
12 | 5a89857461 |
13 | 2b39191058 |
14 | 16874a841b |
15 | bd01c5731 |
hex | 714d636c9 |
30414354121 has 2 divisors, whose sum is σ = 30414354122. Its totient is φ = 30414354120.
The previous prime is 30414354097. The next prime is 30414354143. The reversal of 30414354121 is 12145341403.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20832880896 + 9581473225 = 144336^2 + 97885^2 .
It is a cyclic number.
It is not a de Polignac number, because 30414354121 - 221 = 30412256969 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 30414354121.
It is not a weakly prime, because it can be changed into another prime (30414354181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15207177060 + 15207177061.
It is an arithmetic number, because the mean of its divisors is an integer number (15207177061).
Almost surely, 230414354121 is an apocalyptic number.
It is an amenable number.
30414354121 is a deficient number, since it is larger than the sum of its proper divisors (1).
30414354121 is an equidigital number, since it uses as much as digits as its factorization.
30414354121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 30414354121 its reverse (12145341403), we get a palindrome (42559695524).
The spelling of 30414354121 in words is "thirty billion, four hundred fourteen million, three hundred fifty-four thousand, one hundred twenty-one".
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