Base | Representation |
---|---|
bin | 1101110101001100111110… |
… | …10000000100000110001011 |
3 | 10222200200022000011120202122 |
4 | 12322212133100010012023 |
5 | 12441311101303231103 |
6 | 144404340114121455 |
7 | 6256302234421322 |
oct | 672463720040613 |
9 | 128620260146678 |
10 | 30415335211403 |
11 | 976708688978a |
12 | 34b284228028b |
13 | 13c81ccba247c |
14 | 7721780b10b9 |
15 | 37b28cb4db38 |
hex | 1ba99f40418b |
30415335211403 has 2 divisors, whose sum is σ = 30415335211404. Its totient is φ = 30415335211402.
The previous prime is 30415335211297. The next prime is 30415335211423. The reversal of 30415335211403 is 30411253351403.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 30415335211403 - 238 = 30140457304459 is a prime.
It is a super-2 number, since 2×304153352114032 (a number of 28 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (30415335211423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15207667605701 + 15207667605702.
It is an arithmetic number, because the mean of its divisors is an integer number (15207667605702).
Almost surely, 230415335211403 is an apocalyptic number.
30415335211403 is a deficient number, since it is larger than the sum of its proper divisors (1).
30415335211403 is an equidigital number, since it uses as much as digits as its factorization.
30415335211403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 30415335211403 its reverse (30411253351403), we get a palindrome (60826588562806).
The spelling of 30415335211403 in words is "thirty trillion, four hundred fifteen billion, three hundred thirty-five million, two hundred eleven thousand, four hundred three".
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