Base | Representation |
---|---|
bin | 101100010001001100001… |
… | …000011010110110100001 |
3 | 101202211020011102021220212 |
4 | 230101030020122312201 |
5 | 344320222203333441 |
6 | 10245310011143505 |
7 | 432533265244235 |
oct | 54211410326641 |
9 | 11684204367825 |
10 | 3042114121121 |
11 | a73176128259 |
12 | 4116b9a44b95 |
13 | 190b408a58ba |
14 | a734c1885c5 |
15 | 541ebb31eeb |
hex | 2c44c21ada1 |
3042114121121 has 2 divisors, whose sum is σ = 3042114121122. Its totient is φ = 3042114121120.
The previous prime is 3042114121103. The next prime is 3042114121147. The reversal of 3042114121121 is 1211214112403.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1972089384721 + 1070024736400 = 1404311^2 + 1034420^2 .
It is a cyclic number.
It is not a de Polignac number, because 3042114121121 - 230 = 3041040379297 is a prime.
It is not a weakly prime, because it can be changed into another prime (3042114124121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1521057060560 + 1521057060561.
It is an arithmetic number, because the mean of its divisors is an integer number (1521057060561).
Almost surely, 23042114121121 is an apocalyptic number.
It is an amenable number.
3042114121121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3042114121121 is an equidigital number, since it uses as much as digits as its factorization.
3042114121121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 3042114121121 its reverse (1211214112403), we get a palindrome (4253328233524).
The spelling of 3042114121121 in words is "three trillion, forty-two billion, one hundred fourteen million, one hundred twenty-one thousand, one hundred twenty-one".
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