3043112040133 has 4 divisors (see below), whose sum is σ = 3319758589248. Its totient is φ = 2766465491020.

The previous prime is 3043112040131. The next prime is 3043112040169. The reversal of 3043112040133 is 3310402113403.

3043112040133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 3043112040133 - 2¹ = 3043112040131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3043112040098 and 3043112040107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3043112040131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138323274541 + ... + 138323274562.

It is an arithmetic number, because the mean of its divisors is an integer number (829939647312).

Almost surely, 2^{3043112040133} is an apocalyptic number.

It is an amenable number.

3043112040133 is a deficient number, since it is larger than the sum of its proper divisors (276646549115).

3043112040133 is a wasteful number, since it uses less digits than its factorization.

3043112040133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 276646549114.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 3043112040133 its reverse (3310402113403), we get a palindrome (6353514153536).

The spelling of 3043112040133 in words is "three trillion, forty-three billion, one hundred twelve million, forty thousand, one hundred thirty-three".