Base | Representation |
---|---|
bin | 101100010011111110010… |
… | …010100011111000110001 |
3 | 101210002221110202101001211 |
4 | 230103332102203320301 |
5 | 344342332344432032 |
6 | 10250522344000121 |
7 | 433000331325343 |
oct | 54237622437061 |
9 | 11702843671054 |
10 | 3045103124017 |
11 | a7446a367389 |
12 | 4121b2a60041 |
13 | 1911c8c09776 |
14 | a755312b293 |
15 | 54324252747 |
hex | 2c4fe4a3e31 |
3045103124017 has 2 divisors, whose sum is σ = 3045103124018. Its totient is φ = 3045103124016.
The previous prime is 3045103123957. The next prime is 3045103124083. The reversal of 3045103124017 is 7104213015403.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1866827609761 + 1178275514256 = 1366319^2 + 1085484^2 .
It is a cyclic number.
It is not a de Polignac number, because 3045103124017 - 27 = 3045103123889 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3045103124017.
It is not a weakly prime, because it can be changed into another prime (3045103125017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1522551562008 + 1522551562009.
It is an arithmetic number, because the mean of its divisors is an integer number (1522551562009).
Almost surely, 23045103124017 is an apocalyptic number.
It is an amenable number.
3045103124017 is a deficient number, since it is larger than the sum of its proper divisors (1).
3045103124017 is an equidigital number, since it uses as much as digits as its factorization.
3045103124017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
The spelling of 3045103124017 in words is "three trillion, forty-five billion, one hundred three million, one hundred twenty-four thousand, seventeen".
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