Base | Representation |
---|---|
bin | 1101110110010011010110… |
… | …11101100010100000001111 |
3 | 10222211021211100212021020002 |
4 | 12323021223131202200033 |
5 | 12442420442441044010 |
6 | 144433545355314515 |
7 | 6262110504545213 |
oct | 673115335424017 |
9 | 128737740767202 |
10 | 30453121034255 |
11 | 9781106a04757 |
12 | 34ba02874ba3b |
13 | 13cb9422cb42a |
14 | 773d20590943 |
15 | 37c2500681a5 |
hex | 1bb26b76280f |
30453121034255 has 4 divisors (see below), whose sum is σ = 36543745241112. Its totient is φ = 24362496827400.
The previous prime is 30453121034251. The next prime is 30453121034267. The reversal of 30453121034255 is 55243012135403.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 30453121034255 - 22 = 30453121034251 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30453121034251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3045312103421 + ... + 3045312103430.
It is an arithmetic number, because the mean of its divisors is an integer number (9135936310278).
Almost surely, 230453121034255 is an apocalyptic number.
30453121034255 is a deficient number, since it is larger than the sum of its proper divisors (6090624206857).
30453121034255 is an equidigital number, since it uses as much as digits as its factorization.
30453121034255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6090624206856.
The product of its (nonzero) digits is 216000, while the sum is 38.
Adding to 30453121034255 its reverse (55243012135403), we get a palindrome (85696133169658).
The spelling of 30453121034255 in words is "thirty trillion, four hundred fifty-three billion, one hundred twenty-one million, thirty-four thousand, two hundred fifty-five".
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