Base | Representation |
---|---|
bin | 101100010100010111011… |
… | …100010010100111101011 |
3 | 101210011000212210020022222 |
4 | 230110113130102213223 |
5 | 344344213411331011 |
6 | 10251032300304255 |
7 | 433013644160105 |
oct | 54242734224753 |
9 | 11704025706288 |
10 | 3045525105131 |
11 | a74666586003 |
12 | 4122b024208b |
13 | 191265476132 |
14 | a75931b4575 |
15 | 5434b308ddb |
hex | 2c5177129eb |
3045525105131 has 2 divisors, whose sum is σ = 3045525105132. Its totient is φ = 3045525105130.
The previous prime is 3045525105097. The next prime is 3045525105163. The reversal of 3045525105131 is 1315015255403.
It is a strong prime.
It is an emirp because it is prime and its reverse (1315015255403) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3045525105131 - 214 = 3045525088747 is a prime.
It is a super-2 number, since 2×30455251051312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3045525105091 and 3045525105100.
It is not a weakly prime, because it can be changed into another prime (3045525105031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1522762552565 + 1522762552566.
It is an arithmetic number, because the mean of its divisors is an integer number (1522762552566).
Almost surely, 23045525105131 is an apocalyptic number.
3045525105131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3045525105131 is an equidigital number, since it uses as much as digits as its factorization.
3045525105131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45000, while the sum is 35.
The spelling of 3045525105131 in words is "three trillion, forty-five billion, five hundred twenty-five million, one hundred five thousand, one hundred thirty-one".
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