Base | Representation |
---|---|
bin | 11100011000001110… |
… | …011100010000010000 |
3 | 2220122120221211222100 |
4 | 130120032130100100 |
5 | 444401112210000 |
6 | 21555343440400 |
7 | 2126051003640 |
oct | 343016342020 |
9 | 86576854870 |
10 | 30471210000 |
11 | 11a17227090 |
12 | 5aa48b6100 |
13 | 2b47ba9b9a |
14 | 1690c68520 |
15 | bd51a6a00 |
hex | 71839c410 |
30471210000 has 600 divisors, whose sum is σ = 132887012544. Its totient is φ = 6330240000.
The previous prime is 30471209983. The next prime is 30471210017. The reversal of 30471210000 is 1217403.
It is an interprime number because it is at equal distance from previous prime (30471209983) and next prime (30471210017).
It is a tau number, because it is divible by the number of its divisors (600).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 6927802 + ... + 6932198.
Almost surely, 230471210000 is an apocalyptic number.
30471210000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 30471210000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (66443506272).
30471210000 is an abundant number, since it is smaller than the sum of its proper divisors (102415802544).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
30471210000 is a wasteful number, since it uses less digits than its factorization.
30471210000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4449 (or 4425 counting only the distinct ones).
The product of its (nonzero) digits is 168, while the sum is 18.
Adding to 30471210000 its reverse (1217403), we get a palindrome (30472427403).
It can be divided in two parts, 30471 and 210000, that added together give a triangular number (240471 = T693).
The spelling of 30471210000 in words is "thirty billion, four hundred seventy-one million, two hundred ten thousand".
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