Base | Representation |
---|---|
bin | 1101111000000011111001… |
… | …11110100101010010101001 |
3 | 11000001001210101011212212220 |
4 | 12330001330332211102221 |
5 | 12444413214334414431 |
6 | 144521421231024253 |
7 | 6266350035244605 |
oct | 674017476452251 |
9 | 130031711155786 |
10 | 30513544451241 |
11 | 97a47a33a1205 |
12 | 350989036b089 |
13 | 14045516a86c7 |
14 | 776c13382505 |
15 | 37dad9a57b96 |
hex | 1bc07cfa54a9 |
30513544451241 has 32 divisors (see below), whose sum is σ = 41719785153408. Its totient is φ = 19830195141120.
The previous prime is 30513544451237. The next prime is 30513544451249. The reversal of 30513544451241 is 14215444531503.
It is not a de Polignac number, because 30513544451241 - 22 = 30513544451237 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 30513544451193 and 30513544451202.
It is not an unprimeable number, because it can be changed into a prime (30513544451249) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14519535 + ... + 16487691.
It is an arithmetic number, because the mean of its divisors is an integer number (1303743286044).
Almost surely, 230513544451241 is an apocalyptic number.
It is an amenable number.
30513544451241 is a deficient number, since it is larger than the sum of its proper divisors (11206240702167).
30513544451241 is a wasteful number, since it uses less digits than its factorization.
30513544451241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1968841.
The product of its (nonzero) digits is 576000, while the sum is 42.
Adding to 30513544451241 its reverse (14215444531503), we get a palindrome (44728988982744).
The spelling of 30513544451241 in words is "thirty trillion, five hundred thirteen billion, five hundred forty-four million, four hundred fifty-one thousand, two hundred forty-one".
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