Base | Representation |
---|---|
bin | 101100011010111010001… |
… | …010001000111110100111 |
3 | 101210211011110100220012211 |
4 | 230122322022020332213 |
5 | 400003110300004201 |
6 | 10254153324224251 |
7 | 433353014614552 |
oct | 54327212107647 |
9 | 11724143326184 |
10 | 3052550000551 |
11 | a776409939a7 |
12 | 41373099b087 |
13 | 191b1498779c |
14 | a7a5c171699 |
15 | 5460cdde651 |
hex | 2c6ba288fa7 |
3052550000551 has 4 divisors (see below), whose sum is σ = 3052569920400. Its totient is φ = 3052530080704.
The previous prime is 3052550000483. The next prime is 3052550000603. The reversal of 3052550000551 is 1550000552503.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3052550000551 - 223 = 3052541611943 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3052550000051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9728266 + ... + 10037143.
It is an arithmetic number, because the mean of its divisors is an integer number (763142480100).
Almost surely, 23052550000551 is an apocalyptic number.
3052550000551 is a deficient number, since it is larger than the sum of its proper divisors (19919849).
3052550000551 is a wasteful number, since it uses less digits than its factorization.
3052550000551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19919848.
The product of its (nonzero) digits is 18750, while the sum is 31.
The spelling of 3052550000551 in words is "three trillion, fifty-two billion, five hundred fifty million, five hundred fifty-one", and thus it is an aban number.
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