Base | Representation |
---|---|
bin | 1101111000100010100011… |
… | …11101001011000011011011 |
3 | 11000002122021100221221022211 |
4 | 12330101101331023003123 |
5 | 13000200421121434043 |
6 | 144533142312455551 |
7 | 6300501631514206 |
oct | 674212175130333 |
9 | 130078240857284 |
10 | 30530002530523 |
11 | 9800779570821 |
12 | 3510b040aa5b7 |
13 | 1405c75329b62 |
14 | 7779350b693d |
15 | 37e24e885a9d |
hex | 1bc451f4b0db |
30530002530523 has 2 divisors, whose sum is σ = 30530002530524. Its totient is φ = 30530002530522.
The previous prime is 30530002530451. The next prime is 30530002530527. The reversal of 30530002530523 is 32503520003503.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 30530002530523 - 217 = 30530002399451 is a prime.
It is not a weakly prime, because it can be changed into another prime (30530002530527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15265001265261 + 15265001265262.
It is an arithmetic number, because the mean of its divisors is an integer number (15265001265262).
Almost surely, 230530002530523 is an apocalyptic number.
30530002530523 is a deficient number, since it is larger than the sum of its proper divisors (1).
30530002530523 is an equidigital number, since it uses as much as digits as its factorization.
30530002530523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 31.
The spelling of 30530002530523 in words is "thirty trillion, five hundred thirty billion, two million, five hundred thirty thousand, five hundred twenty-three".
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