Base | Representation |
---|---|
bin | 101100011011010111000… |
… | …000011111110111011001 |
3 | 101210212102012010020021021 |
4 | 230123113000133313121 |
5 | 400010103201341441 |
6 | 10254313334242441 |
7 | 433401012631162 |
oct | 54332700376731 |
9 | 11725365106237 |
10 | 3053034012121 |
11 | a7786a11aa65 |
12 | 413846ab6421 |
13 | 191b91032372 |
14 | a7aa6564769 |
15 | 5463a64a3d1 |
hex | 2c6d701fdd9 |
3053034012121 has 4 divisors (see below), whose sum is σ = 3053041166644. Its totient is φ = 3053026857600.
The previous prime is 3053034012113. The next prime is 3053034012139. The reversal of 3053034012121 is 1212104303503.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2322332166400 + 730701845721 = 1523920^2 + 854811^2 .
It is a cyclic number.
It is not a de Polignac number, because 3053034012121 - 23 = 3053034012113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3053034012421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2893620 + ... + 3805141.
It is an arithmetic number, because the mean of its divisors is an integer number (763260291661).
Almost surely, 23053034012121 is an apocalyptic number.
It is an amenable number.
3053034012121 is a deficient number, since it is larger than the sum of its proper divisors (7154523).
3053034012121 is an equidigital number, since it uses as much as digits as its factorization.
3053034012121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7154522.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 3053034012121 its reverse (1212104303503), we get a palindrome (4265138315624).
The spelling of 3053034012121 in words is "three trillion, fifty-three billion, thirty-four million, twelve thousand, one hundred twenty-one".
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