Base | Representation |
---|---|
bin | 100010101101011000110100… |
… | …0101101100011010000111111 |
3 | 1111000222220010011100211010101 |
4 | 1011122301220231203100333 |
5 | 310004110033240242010 |
6 | 3001155140030021531 |
7 | 121210400523664330 |
oct | 10532615055432077 |
9 | 1430886104324111 |
10 | 305305212040255 |
11 | 893092389a7269 |
12 | 2a2aa2419478a7 |
13 | 10148209067c6b |
14 | 5556bcb61a287 |
15 | 2546a510cc73a |
hex | 115ac68b6343f |
305305212040255 has 64 divisors (see below), whose sum is σ = 457642219438080. Its totient is φ = 190678283827200.
The previous prime is 305305212040237. The next prime is 305305212040421. The reversal of 305305212040255 is 552040212503503.
It is not a de Polignac number, because 305305212040255 - 215 = 305305212007487 is a prime.
It is a super-2 number, since 2×3053052120402552 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2095666506 + ... + 2095812184.
It is an arithmetic number, because the mean of its divisors is an integer number (7150659678720).
Almost surely, 2305305212040255 is an apocalyptic number.
305305212040255 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
305305212040255 is a deficient number, since it is larger than the sum of its proper divisors (152337007397825).
305305212040255 is a wasteful number, since it uses less digits than its factorization.
305305212040255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 259360.
The product of its (nonzero) digits is 180000, while the sum is 37.
Adding to 305305212040255 its reverse (552040212503503), we get a palindrome (857345424543758).
The spelling of 305305212040255 in words is "three hundred five trillion, three hundred five billion, two hundred twelve million, forty thousand, two hundred fifty-five".
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