Base | Representation |
---|---|
bin | 101100011011100111000… |
… | …000101110000010001001 |
3 | 101210220002220100010002112 |
4 | 230123213000232002021 |
5 | 400011130420134414 |
6 | 10254400125112105 |
7 | 433410453036056 |
oct | 54334700560211 |
9 | 11726086303075 |
10 | 3053302505609 |
11 | a77997735104 |
12 | 4139009b8635 |
13 | 191c0484b555 |
14 | a7ad009602d |
15 | 54653ed3d3e |
hex | 2c6e702e089 |
3053302505609 has 2 divisors, whose sum is σ = 3053302505610. Its totient is φ = 3053302505608.
The previous prime is 3053302505551. The next prime is 3053302505623. The reversal of 3053302505609 is 9065052033503.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3013685584009 + 39616921600 = 1735997^2 + 199040^2 .
It is an emirp because it is prime and its reverse (9065052033503) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3053302505609 is a prime.
It is not a weakly prime, because it can be changed into another prime (3053302505629) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526651252804 + 1526651252805.
It is an arithmetic number, because the mean of its divisors is an integer number (1526651252805).
Almost surely, 23053302505609 is an apocalyptic number.
It is an amenable number.
3053302505609 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053302505609 is an equidigital number, since it uses as much as digits as its factorization.
3053302505609 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 364500, while the sum is 41.
The spelling of 3053302505609 in words is "three trillion, fifty-three billion, three hundred two million, five hundred five thousand, six hundred nine".
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