Base | Representation |
---|---|
bin | 100010101101101010111000… |
… | …1010111101010011011011011 |
3 | 1111001010121021012100011000220 |
4 | 1011123111301113222123123 |
5 | 310010224014033044120 |
6 | 3001225034055531123 |
7 | 121213243160143335 |
oct | 10533256127523333 |
9 | 1431117235304026 |
10 | 305344012003035 |
11 | 89323739523605 |
12 | 2a2b586b989aa3 |
13 | 1014ba80612115 |
14 | 5558a2c688455 |
15 | 2547a7256cb40 |
hex | 115b5715ea6db |
305344012003035 has 32 divisors (see below), whose sum is σ = 489825961363008. Its totient is φ = 162425053900800.
The previous prime is 305344012003031. The next prime is 305344012003111. The reversal of 305344012003035 is 530300210443503.
It is not a de Polignac number, because 305344012003035 - 22 = 305344012003031 is a prime.
It is a super-2 number, since 2×3053440120030352 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 305344012002987 and 305344012003005.
It is not an unprimeable number, because it can be changed into a prime (305344012003031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 48605919 + ... + 54527271.
It is an arithmetic number, because the mean of its divisors is an integer number (15307061292594).
Almost surely, 2305344012003035 is an apocalyptic number.
305344012003035 is a deficient number, since it is larger than the sum of its proper divisors (184481949359973).
305344012003035 is a wasteful number, since it uses less digits than its factorization.
305344012003035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5930335.
The product of its (nonzero) digits is 64800, while the sum is 33.
Adding to 305344012003035 its reverse (530300210443503), we get a palindrome (835644222446538).
The spelling of 305344012003035 in words is "three hundred five trillion, three hundred forty-four billion, twelve million, three thousand, thirty-five".
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