Base | Representation |
---|---|
bin | 100010101101101010111000… |
… | …1010111101010011100100111 |
3 | 1111001010121021012100011010201 |
4 | 1011123111301113222130213 |
5 | 310010224014033044421 |
6 | 3001225034055531331 |
7 | 121213243160143504 |
oct | 10533256127523447 |
9 | 1431117235304121 |
10 | 305344012003111 |
11 | 89323739523674 |
12 | 2a2b586b989b47 |
13 | 1014ba80612173 |
14 | 5558a2c6884ab |
15 | 2547a7256cb91 |
hex | 115b5715ea727 |
305344012003111 has 2 divisors, whose sum is σ = 305344012003112. Its totient is φ = 305344012003110.
The previous prime is 305344012003031. The next prime is 305344012003127. The reversal of 305344012003111 is 111300210443503.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 305344012003111 - 221 = 305344009905959 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 305344012003111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (305344012003211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 152672006001555 + 152672006001556.
It is an arithmetic number, because the mean of its divisors is an integer number (152672006001556).
Almost surely, 2305344012003111 is an apocalyptic number.
305344012003111 is a deficient number, since it is larger than the sum of its proper divisors (1).
305344012003111 is an equidigital number, since it uses as much as digits as its factorization.
305344012003111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 305344012003111 its reverse (111300210443503), we get a palindrome (416644222446614).
The spelling of 305344012003111 in words is "three hundred five trillion, three hundred forty-four billion, twelve million, three thousand, one hundred eleven".
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