Base | Representation |
---|---|
bin | 101100011011110001010… |
… | …100001001101101100001 |
3 | 101210220112221121122000202 |
4 | 230123301110021231201 |
5 | 400012004143344443 |
6 | 10254425222154545 |
7 | 433414652263253 |
oct | 54336124115541 |
9 | 11726487548022 |
10 | 3053475371873 |
11 | a77a76275093 |
12 | 41394a882a55 |
13 | 191c315c5394 |
14 | a7b09013cd3 |
15 | 5466427d7b8 |
hex | 2c6f1509b61 |
3053475371873 has 2 divisors, whose sum is σ = 3053475371874. Its totient is φ = 3053475371872.
The previous prime is 3053475371861. The next prime is 3053475372041. The reversal of 3053475371873 is 3781735743503.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2558502619024 + 494972752849 = 1599532^2 + 703543^2 .
It is an emirp because it is prime and its reverse (3781735743503) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3053475371873 - 222 = 3053471177569 is a prime.
It is not a weakly prime, because it can be changed into another prime (3053475371803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526737685936 + 1526737685937.
It is an arithmetic number, because the mean of its divisors is an integer number (1526737685937).
Almost surely, 23053475371873 is an apocalyptic number.
It is an amenable number.
3053475371873 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053475371873 is an equidigital number, since it uses as much as digits as its factorization.
3053475371873 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22226400, while the sum is 56.
The spelling of 3053475371873 in words is "three trillion, fifty-three billion, four hundred seventy-five million, three hundred seventy-one thousand, eight hundred seventy-three".
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