Base | Representation |
---|---|
bin | 101100011011110100101… |
… | …001001001001011000011 |
3 | 101210220200211200022111221 |
4 | 230123310221021023003 |
5 | 400012112442100324 |
6 | 10254434535015511 |
7 | 433416231001045 |
oct | 54336451111303 |
9 | 11726624608457 |
10 | 3053531206339 |
11 | a77aa4840379 |
12 | 41396550a597 |
13 | 191c40044323 |
14 | a7b125c9a95 |
15 | 5466910c0e4 |
hex | 2c6f4a492c3 |
3053531206339 has 2 divisors, whose sum is σ = 3053531206340. Its totient is φ = 3053531206338.
The previous prime is 3053531206301. The next prime is 3053531206463. The reversal of 3053531206339 is 9336021353503.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3053531206339 - 213 = 3053531198147 is a prime.
It is a super-2 number, since 2×30535312063392 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3053531206295 and 3053531206304.
It is not a weakly prime, because it can be changed into another prime (3053531236339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526765603169 + 1526765603170.
It is an arithmetic number, because the mean of its divisors is an integer number (1526765603170).
Almost surely, 23053531206339 is an apocalyptic number.
3053531206339 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053531206339 is an equidigital number, since it uses as much as digits as its factorization.
3053531206339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 656100, while the sum is 43.
The spelling of 3053531206339 in words is "three trillion, fifty-three billion, five hundred thirty-one million, two hundred six thousand, three hundred thirty-nine".
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