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30540152111234 = 215270076055617
BaseRepresentation
bin1101111000110101011101…
…11010110000000010000010
311000010121110201012001121112
412330122232322300002002
513000332212420024414
6144541541401323322
76301311303521423
oct674325672600202
9130117421161545
1030540152111234
119805007760a57
123512a77196542
131406c01cca40c
1477821905564a
1537e64593dd3e
hex1bc6aeeb0082

30540152111234 has 4 divisors (see below), whose sum is σ = 45810228166854. Its totient is φ = 15270076055616.

The previous prime is 30540152111219. The next prime is 30540152111237. The reversal of 30540152111234 is 43211125104503.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 30376665319009 + 163486792225 = 5511503^2 + 404335^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 30540152111234.

It is not an unprimeable number, because it can be changed into a prime (30540152111237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7635038027807 + ... + 7635038027810.

Almost surely, 230540152111234 is an apocalyptic number.

30540152111234 is a deficient number, since it is larger than the sum of its proper divisors (15270076055620).

30540152111234 is a wasteful number, since it uses less digits than its factorization.

30540152111234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15270076055619.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 30540152111234 its reverse (43211125104503), we get a palindrome (73751277215737).

The spelling of 30540152111234 in words is "thirty trillion, five hundred forty billion, one hundred fifty-two million, one hundred eleven thousand, two hundred thirty-four".

Divisors: 1 2 15270076055617 30540152111234