Base | Representation |
---|---|
bin | 1101111000110101100111… |
… | …10000100111010011110111 |
3 | 11000010121200101000220201221 |
4 | 12330122303300213103313 |
5 | 13000332344213341101 |
6 | 144541553422331211 |
7 | 6301313311123423 |
oct | 674326360472367 |
9 | 130117611026657 |
10 | 30540233340151 |
11 | 98050495a1497 |
12 | 3512a9a429b07 |
13 | 1406c15a9ac72 |
14 | 778225b5bb83 |
15 | 37e64cb36aa1 |
hex | 1bc6b3c274f7 |
30540233340151 has 4 divisors (see below), whose sum is σ = 30540261416112. Its totient is φ = 30540205264192.
The previous prime is 30540233340143. The next prime is 30540233340191. The reversal of 30540233340151 is 15104333204503.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 30540233340151 - 23 = 30540233340143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30540233340101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12337675 + ... + 14604748.
It is an arithmetic number, because the mean of its divisors is an integer number (7635065354028).
Almost surely, 230540233340151 is an apocalyptic number.
30540233340151 is a deficient number, since it is larger than the sum of its proper divisors (28075961).
30540233340151 is a wasteful number, since it uses less digits than its factorization.
30540233340151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28075960.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 30540233340151 its reverse (15104333204503), we get a palindrome (45644566544654).
The spelling of 30540233340151 in words is "thirty trillion, five hundred forty billion, two hundred thirty-three million, three hundred forty thousand, one hundred fifty-one".
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