Base | Representation |
---|---|
bin | 101100011100011101001… |
… | …110011001010100110111 |
3 | 101210222110021211021210122 |
4 | 230130131032121110313 |
5 | 400020011241413341 |
6 | 10255030300042155 |
7 | 433442136111365 |
oct | 54343516312467 |
9 | 11728407737718 |
10 | 3054212060471 |
11 | a783140a3140 |
12 | 413b1553335b |
13 | 19201b10bcb0 |
14 | a7b78bbc635 |
15 | 546a8c9b94b |
hex | 2c71d399537 |
3054212060471 has 64 divisors (see below), whose sum is σ = 3660014768256. Its totient is φ = 2512283904000.
The previous prime is 3054212060429. The next prime is 3054212060489. The reversal of 3054212060471 is 1740602124503.
It is not a de Polignac number, because 3054212060471 - 26 = 3054212060407 is a prime.
It is a super-3 number, since 3×30542120604713 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3054212060671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 664390145 + ... + 664394741.
It is an arithmetic number, because the mean of its divisors is an integer number (57187730754).
Almost surely, 23054212060471 is an apocalyptic number.
3054212060471 is a deficient number, since it is larger than the sum of its proper divisors (605802707785).
3054212060471 is a wasteful number, since it uses less digits than its factorization.
3054212060471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5172.
The product of its (nonzero) digits is 40320, while the sum is 35.
Adding to 3054212060471 its reverse (1740602124503), we get a palindrome (4794814184974).
The spelling of 3054212060471 in words is "three trillion, fifty-four billion, two hundred twelve million, sixty thousand, four hundred seventy-one".
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