Base | Representation |
---|---|
bin | 1011011000010000… |
… | …1010011000110001 |
3 | 21212212122221020022 |
4 | 2312010022120301 |
5 | 22223430410213 |
6 | 1223033253225 |
7 | 135460125233 |
oct | 26604123061 |
9 | 7785587208 |
10 | 3054544433 |
11 | 1328235496 |
12 | 712b64215 |
13 | 398aa1255 |
14 | 20d964253 |
15 | 12d26a308 |
hex | b610a631 |
3054544433 has 2 divisors, whose sum is σ = 3054544434. Its totient is φ = 3054544432.
The previous prime is 3054544399. The next prime is 3054544447. The reversal of 3054544433 is 3344454503.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3052783504 + 1760929 = 55252^2 + 1327^2 .
It is a cyclic number.
It is not a de Polignac number, because 3054544433 - 210 = 3054543409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3054544393 and 3054544402.
It is not a weakly prime, because it can be changed into another prime (3054544133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1527272216 + 1527272217.
It is an arithmetic number, because the mean of its divisors is an integer number (1527272217).
Almost surely, 23054544433 is an apocalyptic number.
It is an amenable number.
3054544433 is a deficient number, since it is larger than the sum of its proper divisors (1).
3054544433 is an equidigital number, since it uses as much as digits as its factorization.
3054544433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 35.
The square root of 3054544433 is about 55267.9331348658. The cubic root of 3054544433 is about 1450.9378685575.
Adding to 3054544433 its reverse (3344454503), we get a palindrome (6398998936).
The spelling of 3054544433 in words is "three billion, fifty-four million, five hundred forty-four thousand, four hundred thirty-three".
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