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30552254022281 is a prime number
BaseRepresentation
bin1101111001001100000000…
…01111111000001010001001
311000011202201010001211122012
412330212000033320022021
513001032004012203111
6144551302311305305
76302220223210055
oct674460017701211
9130152633054565
1030552254022281
11980a157999932
12351529407b235
1314080b02c4524
14778a46400c65
1537eb030e048b
hex1bc9803f8289

30552254022281 has 2 divisors, whose sum is σ = 30552254022282. Its totient is φ = 30552254022280.

The previous prime is 30552254022223. The next prime is 30552254022299. The reversal of 30552254022281 is 18222045225503.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28042754482681 + 2509499539600 = 5295541^2 + 1584140^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-30552254022281 is a prime.

It is a super-2 number, since 2×305522540222812 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (30552254028281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15276127011140 + 15276127011141.

It is an arithmetic number, because the mean of its divisors is an integer number (15276127011141).

Almost surely, 230552254022281 is an apocalyptic number.

It is an amenable number.

30552254022281 is a deficient number, since it is larger than the sum of its proper divisors (1).

30552254022281 is an equidigital number, since it uses as much as digits as its factorization.

30552254022281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384000, while the sum is 41.

Adding to 30552254022281 its reverse (18222045225503), we get a palindrome (48774299247784).

The spelling of 30552254022281 in words is "thirty trillion, five hundred fifty-two billion, two hundred fifty-four million, twenty-two thousand, two hundred eighty-one".