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30552254022490 = 2521403314274553
BaseRepresentation
bin1101111001001100000000…
…01111111000001101011010
311000011202201010001211220221
412330212000033320031122
513001032004012204430
6144551302311310254
76302220223210504
oct674460017701532
9130152633054827
1030552254022490
11980a15799a002
12351529407b38a
1314080b02c4655
14778a46400d74
1537eb030e057a
hex1bc9803f835a

30552254022490 has 16 divisors (see below), whose sum is σ = 54994318035048. Its totient is φ = 12220843654656.

The previous prime is 30552254022469. The next prime is 30552254022491. The reversal of 30552254022490 is 9422045225503.

It can be written as a sum of positive squares in 4 ways, for example, as 30293806848361 + 258447174129 = 5503981^2 + 508377^2 .

It is a super-4 number, since 4×305522540224904 (a number of 55 digits) contains 4444 as substring.

It is not an unprimeable number, because it can be changed into a prime (30552254022491) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4996947 + ... + 9277606.

Almost surely, 230552254022490 is an apocalyptic number.

30552254022490 is a deficient number, since it is larger than the sum of its proper divisors (24442064012558).

30552254022490 is a wasteful number, since it uses less digits than its factorization.

30552254022490 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14488593.

The product of its (nonzero) digits is 864000, while the sum is 43.

Adding to 30552254022490 its reverse (9422045225503), we get a palindrome (39974299247993).

The spelling of 30552254022490 in words is "thirty trillion, five hundred fifty-two billion, two hundred fifty-four million, twenty-two thousand, four hundred ninety".

Divisors: 1 2 5 10 214033 428066 1070165 2140330 14274553 28549106 71372765 142745530 3055225402249 6110450804498 15276127011245 30552254022490