Base | Representation |
---|---|
bin | 101100011101101111000… |
… | …101011101010101100001 |
3 | 101211010000000002200010001 |
4 | 230131233011131111201 |
5 | 400030314333334223 |
6 | 10255414440340001 |
7 | 433521153531445 |
oct | 54355705352541 |
9 | 11733000080101 |
10 | 3055585449313 |
11 | a78959366541 |
12 | 414239474601 |
13 | 1921a9801107 |
14 | a7c69364825 |
15 | 547396369ad |
hex | 2c76f15d561 |
3055585449313 has 2 divisors, whose sum is σ = 3055585449314. Its totient is φ = 3055585449312.
The previous prime is 3055585449271. The next prime is 3055585449361. The reversal of 3055585449313 is 3139445855503.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2924315463969 + 131269985344 = 1710063^2 + 362312^2 .
It is a cyclic number.
It is not a de Polignac number, because 3055585449313 - 217 = 3055585318241 is a prime.
It is not a weakly prime, because it can be changed into another prime (3055585449013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1527792724656 + 1527792724657.
It is an arithmetic number, because the mean of its divisors is an integer number (1527792724657).
Almost surely, 23055585449313 is an apocalyptic number.
It is an amenable number.
3055585449313 is a deficient number, since it is larger than the sum of its proper divisors (1).
3055585449313 is an equidigital number, since it uses as much as digits as its factorization.
3055585449313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440000, while the sum is 55.
The spelling of 3055585449313 in words is "three trillion, fifty-five billion, five hundred eighty-five million, four hundred forty-nine thousand, three hundred thirteen".
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