Base | Representation |
---|---|
bin | 101100011110001001101… |
… | …100000011100011100011 |
3 | 101211011011002221100210002 |
4 | 230132021230003203203 |
5 | 400032223113244242 |
6 | 10255531022530215 |
7 | 433535213325404 |
oct | 54361154034343 |
9 | 11734132840702 |
10 | 3056031774947 |
11 | a790682a25a8 |
12 | 414342a3696b |
13 | 19224b112518 |
14 | a7cac7479ab |
15 | 547638eb432 |
hex | 2c789b038e3 |
3056031774947 has 2 divisors, whose sum is σ = 3056031774948. Its totient is φ = 3056031774946.
The previous prime is 3056031774931. The next prime is 3056031774953. The reversal of 3056031774947 is 7494771306503.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3056031774947 - 24 = 3056031774931 is a prime.
It is a super-2 number, since 2×30560317749472 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3056031774892 and 3056031774901.
It is not a weakly prime, because it can be changed into another prime (3056031774907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1528015887473 + 1528015887474.
It is an arithmetic number, because the mean of its divisors is an integer number (1528015887474).
Almost surely, 23056031774947 is an apocalyptic number.
3056031774947 is a deficient number, since it is larger than the sum of its proper divisors (1).
3056031774947 is an equidigital number, since it uses as much as digits as its factorization.
3056031774947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13335840, while the sum is 56.
The spelling of 3056031774947 in words is "three trillion, fifty-six billion, thirty-one million, seven hundred seventy-four thousand, nine hundred forty-seven".
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