Base | Representation |
---|---|
bin | 1101111011110011011010… |
… | …10101111000100111001011 |
3 | 11000111100200210201122020022 |
4 | 12331321231111320213023 |
5 | 13004020041033034430 |
6 | 145100444542051055 |
7 | 6311551401141242 |
oct | 675715525704713 |
9 | 130440623648208 |
10 | 30642131143115 |
11 | 9844289211a98 |
12 | 352a797879a8b |
13 | 141370482222b |
14 | 77d130c73959 |
15 | 3821137984e5 |
hex | 1bde6d5789cb |
30642131143115 has 8 divisors (see below), whose sum is σ = 36975979481040. Its totient is φ = 24376756841632.
The previous prime is 30642131143081. The next prime is 30642131143121. The reversal of 30642131143115 is 51134113124603.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 30642131143115 - 212 = 30642131139019 is a prime.
It is a super-2 number, since 2×306421311431152 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17118508124 + ... + 17118509913.
It is an arithmetic number, because the mean of its divisors is an integer number (4621997435130).
Almost surely, 230642131143115 is an apocalyptic number.
30642131143115 is a deficient number, since it is larger than the sum of its proper divisors (6333848337925).
30642131143115 is a wasteful number, since it uses less digits than its factorization.
30642131143115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34237018221.
The product of its (nonzero) digits is 25920, while the sum is 35.
Adding to 30642131143115 its reverse (51134113124603), we get a palindrome (81776244267718).
The spelling of 30642131143115 in words is "thirty trillion, six hundred forty-two billion, one hundred thirty-one million, one hundred forty-three thousand, one hundred fifteen".
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